Remove Nth Node From End of List

Given the head of a linked list, remove the nth node from the end of the list and return its head.

 

Example 1:

Input: head = [1,2,3,4,5], n = 2
Output: [1,2,3,5]

Example 2:

Input: head = [1], n = 1
Output: []

Example 3:

Input: head = [1,2], n = 1
Output: [1]

 

Constraints:

• The number of nodes in the list is sz.
• 1 <= sz <= 30
• 0 <= Node.val <= 100
• 1 <= n <= sz

 

Follow up: Could you do this in one pass?

Solution:

/**

* Definition for singly-linked list.

* public class ListNode {

* int val;

* ListNode next;

* ListNode() {}

* ListNode(int val) { this.val = val; }

* ListNode(int val, ListNode next) { this.val = val; this.next = next; }

* }

*/

class Solution {

public ListNode removeNthFromEnd(ListNode head, int n) {

ListNode fast = head;

ListNode slow = head;

for(int i = 0; i < n; i++){

fast = fast.next;

}

if(fast == null) return head.next;

while(fast.next != null){

fast = fast.next;

slow = slow.next;

}

slow.next = slow.next.next;

return head;

}

}